sysFileLongName ( )

Obtains the long path form for an existing file

Usage:

sysFileLongName (object me, string filePath )

Parameters:

filePath (string) - a string specifying the file path to an existing file

Returns:

(string) - the short path form

Example:

xtRose = xtra("Rosetta").new( )
strFilePath = xtRose.sysFileShortName( "c:\progra~1\test.txt" )

Notes: